Robert Griffin III was named NFC Offensive Player of the Week for his performance against the Philadelphia Eagles in Week 11. The Washington Redskins’ quarterback has been given that honor twice in a season, also winning it for his effort in Week 1.
Against the Eagles, Griffin was 14 for 15 for 200 yards and four touchdowns passing the ball and added 84 rushing yards. He had a perfect 158.3 passer rating in the 31-6 rout.
“Basically, we just knew what was at hand, and the hole we dug ourselves in,” Griffin said Tuesday. “I just felt like there was a vibe that we were going to go out there and click.”
Griffin was the main reason why the Redskins were able to move to 4-6 and save their season for at least a few more days. Every decision he made seemed to be the right one. Offensive coordinator Kyle Shanahan praised his young quarterback for letting it go a few times and making plays as a result.
Griffin’s completion percentage of 93.3 was the highest of any quarterback with at least four touchdown passes since Steve Young in 1994.
“He’s been smart with the ball. I think whenever you can make a lot of plays with your legs, too, you don’t feel the pressure that you have to make some bad throws.,” Shanahan said. “Some guys who can’t make plays with their legs, if it’s not there they don’t have [any] other options besides take a sack. So some guys will just let it go and throw it away.
“Robert, if the play’s not there and it doesn’t work, there’s another option and that option’s him running and making a play. He usually takes what the defense gives him. If there’s a guy open, he takes it. If not he tries to make a play himself.”
• Stephen Whyno can be reached at swhyno@washingtontimes.com.
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